A dog chasing a rabbit, rabbit runs 60 leaps before the dog. When the dog jumps 2 leaps rabbit can jumps 3 leaps. But rabbit have to jump 7 leaps to cover the distance that dog cover by 3 leaps. How many leaps that the dog jumps when rabbit and dog meet?
Accepted Solution
A:
Answer:x=vel of d
y=vel oh h
t1=time taken by d
t2=time taken by h
we have 4t1=5t2..............(1)
also
3xt1=4yt2....................(2)
comparing 1 and 2
x/y=16/15Step-by-step explanation: